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.(235)^(239)Pu.(94) is undergoing alpha-...

`._(235)^(239)Pu._(94)` is undergoing `alpha-decay` according to the equation `._(94)^(235)Pu rarr (._(97)^(235)U) +._2^4 He` . The energy released in the process is mostly kinetic energy of the `alpha`-particle. However, a part of the energy is released as `gamma` rays. What is the speed of the emiited `alpha`-particle if the `gamma` rays radiated out have energy of `0.90 MeV`? Given: Mass of `._(94)^(239)Pu =239.05122 u`, mass of `(._(97)^(235)U)=235.04299 u` and mass of `._1^4He =4.002602 u (1u =931 MeV)`.

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