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Atomic weight of boron is 10.81 and it h...

Atomic weight of boron is `10.81` and it has two isotopes `._5 B^10` and `._5 B^11`. Then ratio of `._5 B^10` in nature would be.

A

`19:81`

B

`10:11`

C

`15:16`

D

`81:19`

Text Solution

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The correct Answer is:
A
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The natural boron of atomic weight 10.81 is found to have two isotopes .^10B and .^11B .The ratio of abundance of isotopes of natural boron should be

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