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An alpha particles kinetic energy T= 5.3...

An alpha particles kinetic energy `T= 5.3 MeV` initiates a nuclear reaction `Be^(9)(alpha,n)C^(12)` with energy yield `Q=+5.7MeV`. Find the kinetic energy of the nerutron outgoing at right angle to the motion direction of the alpha-particles.

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The correct Answer is:
`[T_(n) = (Q + (1 -m_(a)//m_(c))T)/(1 + m_(n)//m_(c)) = 8.5 MeV]`
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