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Find the energy required for separation ...

Find the energy required for separation of `a_(10)Ne^(20)` nucleus into two `alpha`-particles and `a_(6)C^(12)` nucleus if it is known that the binding energies per nucleon in `._(10)Ne^(20), ._(2)He^(4)` and `._(6)C^(12)` nuclei are equal to `8.03, 7.07` and `7.68 MeV` respectively.

Text Solution

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The correct Answer is:
[`E = 20 ._(Ne) - 2.4 E_(alpha) - 12 ._(c) = 11.9 MeV`, where E is the B.E per nucleon in the corresponding nucleus]
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