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Taking into account the motion of the nu...

Taking into account the motion of the nucleus of a hydrogen atom , find the expressions for the electron's binding energy in the ground state and for the Rydberg constant. How much (in percent) do the binding energy and the Rydberg constant , obtained without taking into account corresponding values of these of these quantities?

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The correct Answer is:
[`(mue^(4))/(32 pi^(2)epsilon_(0)^(2)ħ^(2)), 0.055%`. Here `ħ = (h)/(2pi)` and `mu = (mM)/(m+M)`]
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