Two plane mirrors are combined to each other as such one is in (y-z) plane and other is in (x-z)plane.A ray of light along vector `(1)/(sqrt(3)) hati +(1)/(sqrt(3))hatj +(1)/(sqrt(3))hatk` is incident on the first mirror. Find the unit vector in the direction of emergence ray after successive reflections through these mirros.

A ray of light is incident on the (y-z) plane mirror along a unit vector hate_(1) = (1)/(sqrt(3)) hati +(1)/(sqrt(3)) hatj +(1)/(sqrt(3))hatk . Find the unit vector along the reflected ray.

Find the unit vector in the direction of the vector veca = 2hati+2sqrt2hatj-3hatk.

The unit vector normal to the plane x + 2y +3z-6 =0 is (1)/(sqrt(14)) hati + (2)/(sqrt(14))hatj + (3)/(sqrt(14))hatk.

The XY plane is the boundary between two tranparednt media. Medium 1 with z ge 0 has a refraxtive index of sqrt2 and medium 2 with z le 0 has a refractive index of sqrt3 . A ray of light in medium 1 given by the vector 6sqrt(3)hat(i)+8sqrt(3)hat(j)-10hatk is incident on teh plane of separation. Find the unit vector in the direction of teh refracted ray in medium 2.

A ray of light travelling in the direction (1)/(2) (hati,+sqrt3hatj) is incident on a plane mirror. After reflection, it travels along the direction (1)/(2) (hati-sqrt3hatj) . The angle of incidence is

A ray of light travelling in the direction 1/2 (hati+sqrt(3)hatj) is incident on a plane mirror. After reflectiion, it travels along the direction 1/2(hati+sqrt(3)hatj) . The angle of incidence is

Two plane mirror are inclined to each other at 90^(@) . A ray of light is incident on one mirror. The ray will undergo a total deviation of

A ray of light is incident on a plane mirror along a vector hat i+hat j- hat k. The normal on incidence point is along hat i+ hat j .Find a unit vector along the reflected ray.