|y|^(x)m^(2)-5m-14

Find the shortest distance from the point M(-7,2) to the circle x^(2)+y^(2)-10x-14y-151=0

Divide: m^(3)-14m^(2)+37m-26 by m^(2)-12m+13x^(4)+x^(2)+1byx^(2)+x+1x^(5)+x^(4)+x^(3)+x^(2)+x+1byx^(3)+1

Add (i)5m(3-m) and 6m^(2)-13m-13m (ii) 4y(3y^(2)+5y-7) and 2(y^(3)-4y^(2)+5)

find the value of x satisfying the simultaneous equations a^(2x)b^(3y)=m^(5) and a^(3x)b^(2y)=m^(10)

If the expression x^(2)-(5m-2)x+(4m^(2)+10m+25) can be expressed as a perfect square then m is

If the expression x^(2)-(5m-2)x+(4m^(2)+10m+25)=0 can be expressed as aperfect square then value of m is

(i) x^(2) - 5x-14 = 0 (ii) 2y^(2) +11y + 14 = 0

The length of the diameter of the circle which cuts three circles x^(2)+y^(2)-xy-14=0 x^(2)+y^(2)+3x-5y-10=0 x^(2)+y^(2)-2x+3y-27=0 M orthogonally, is

The lines x+y-1=0,(m-1)x+(m^(2)-7)y-5=0and(m-2)x+(2m-5)y=0 are -

The lines x+y-1=0,(m-1)x+(m^(2)-7)y-5=0 and (m-2)x+(2m-5)y=0 are concurrent for three values of m concurrent for no value of m parallel for one value of m parallel for two value of m