Let the lengths of the altitudes drawn from the vertices of a A ABC to the opposite siderare 2, 2 and 3. If the area of A ABC is A, then find the value of `2 sqrt 2 triangle`.

Let the lengths of the altitudes drawn from the vertices of Delta ABC to the opposite sides are 2, 2 and 3. If the area of Delta ABC " is " Delta , then find the area of triangle

Let the lengths of the altitudes drawn from the vertices of Delta ABC to the opposite sides are 2, 2 and 3. If the area of Delta ABC " is " Delta , then find the area of triangle

Let the lengths of the altitudes drawn from the vertices of Delta ABC to the opposite sides are 2, 2 and 3. If the area of Delta ABC " is " Delta , then find the area of triangle

Let the lengths of the altitudes drawn from the vertices of Delta ABC to the opposite sides are 2, 2 and 3. If the area of Delta ABC " is " Delta , then find the area of triangle

If p_1,p_2,P_3 are the lengths of the altitudes from the vertices of Delta ABC to the opposite sides

IF p_1,p_2,p_3 are the lengths of the altitudes from the vertices of Delta ABC to the opposite sides, then p_1 p_2 p_3 =

In Delta ABC , the length of the altitude from A to BC is

IF p_1,p_2,p_3 are the lengths of the altitudes from the vertices of Delta ABC to the opposite sides, then (a cotA)/p_1+(b cot B)/p_2+( c cot C)/p_3=

The length of the altitudes from the vertices A,B,C of a triangle ABC to opposite sides are 24,18,(72)/(5) respectively. If Delta is the area of the triangle ABC then root(3)(Delta) is equal to