`(sintheta-2sin^(3)theta)/(2cos^(3)theta-costheta)=tantheta.`

Prove that (sintheta-2sin^3theta)/(2cos^3theta-costheta)=tantheta .

Prove the following identity, where the angles involved are acute angles for which the expressions are defined. (vii) (sintheta-2sin^3theta)/(2cos^3theta-costheta)=tantheta

Prove the following identity, where the angles involved are acute angles for which the expressions are defined. (vii) (sintheta-2sin^3theta)/(2cos^3theta-costheta)=tantheta

Prove the following identity, where the angles involved are acute angles for which the expressions are defined. (vii) (sintheta-2sin^3theta)/(2cos^3theta-costheta)=tantheta

Prove the following (sintheta-2sin^3theta) /(2cos^3theta-costheta) =tantheta

Prove the following identities, where the angles involved are acute angles for which the expressions are defined. : (sintheta-2sin^3theta)/(2cos^3theta-costheta) =tantheta .

Prove that (frac(sintheta-2sin^3theta)(2cos^3theta-costheta))=tantheta

Prove the following identities,where the angles involves are acute angles for which the expressions are defined:(vii) (Sintheta-2Sin^3theta)/(2Cos^3theta-Costheta)=tantheta

(sintheta-2sin^3theta)/(2cos^3theta-costheta) = …………….

Prove that tantheta=(sintheta-2sin^3theta)/(2cos^3theta-costheta)