`cos^2(26^@)+cos64^@sin26^@+(tan36^@)/(cot54^@)`

Evaluate without using trigonometric tables : "cos"^(2) 26^(@)+"cos" 64^(@)"sin" 26^(@)+("tan" 36^(@))/("cot" 54^(@))

The value of (2 sin^2 38^@ sec^2 52^@+ cos64^@ sin26^@+ sin^2 64^@)/(tan^2 23^@+cot^2 23^@-sec^2 67^@-cosec^2 67^@) is: (2 sin^2 38^@ sec^2 52^@+ cos64^@ sin26^@+ sin^2 64^@)/(tan^2 23^@+cot^2 23^@-sec^2 67^@-cosec^2 67^@) का मान ज्ञात कीजिए?

( tan 26^@ )/( cot 64 ^@) = ?

cos54^(@)cos36^(@)-sin54^(@)sin36^(@)=0

Evaluate (tan 36^(@) )/( cot 54^(@))

Evaluate (tan 36^(@) )/( cot 54^(@))

Evaluate (tan 36^(@) )/( cot 54^(@))

Evaluate (tan 36^(@) )/( cot 54^(@))

Evaluate (tan 36^(@) )/( cot 54^(@))