Is the function defined by `f(x)=x^2-sinx+5` continuous at `x=pi`?

Explanation

To determine whether the function \( f(x) = x^2 - \sin x + 5 \) is continuous at \( x = \pi \), we need to check the following condition for continuity:

\[ \lim_{x \to \pi} f(x) = f(\pi) \]

### Step 1: Calculate \( f(\pi) \)

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