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For what value (s) of k is x^(2) - kx + ...

For what value (s) of k is `x^(2) - kx + k` divisible by x - k ?

A

only 0

B

only 0 or `- (1)/(2)`

C

only 1

D

any value of k

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The correct Answer is:
To determine the value(s) of \( k \) for which the polynomial \( x^2 - kx + k \) is divisible by \( x - k \), we can use the Factor Theorem. According to this theorem, a polynomial \( f(x) \) is divisible by \( x - k \) if and only if \( f(k) = 0 \). ### Step-by-Step Solution: 1. **Define the Polynomial**: We have the polynomial \( f(x) = x^2 - kx + k \). 2. **Apply the Factor Theorem**: According to the Factor Theorem, for \( f(x) \) to be divisible by \( x - k \), we need to evaluate \( f(k) \) and set it equal to zero: \[ f(k) = k^2 - k \cdot k + k \] 3. **Simplify the Expression**: Substitute \( k \) into the polynomial: \[ f(k) = k^2 - k^2 + k \] This simplifies to: \[ f(k) = k \] 4. **Set the Expression to Zero**: For \( f(k) \) to be zero, we set: \[ k = 0 \] 5. **Conclusion**: The value of \( k \) for which the polynomial \( x^2 - kx + k \) is divisible by \( x - k \) is: \[ k = 0 \] ### Final Answer: The value of \( k \) is \( 0 \). ---

To determine the value(s) of \( k \) for which the polynomial \( x^2 - kx + k \) is divisible by \( x - k \), we can use the Factor Theorem. According to this theorem, a polynomial \( f(x) \) is divisible by \( x - k \) if and only if \( f(k) = 0 \). ### Step-by-Step Solution: 1. **Define the Polynomial**: We have the polynomial \( f(x) = x^2 - kx + k \). 2. **Apply the Factor Theorem**: ...
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