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-(12)/(5)lt6-9ylt-(9)/(4) In the inequ...

`-(12)/(5)lt6-9ylt-(9)/(4)`
In the inequality above, what is one possible value of `3y-2`?

A

`0.75`

B

`0.76`

C

`0.80`

D

`0.81`

Text Solution

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The correct Answer is:
To solve the inequality \(-\frac{12}{5} < 6 - 9y < -\frac{9}{4}\) and find a possible value of \(3y - 2\), we can follow these steps: ### Step 1: Rewrite the inequality The given inequality is: \[ -\frac{12}{5} < 6 - 9y < -\frac{9}{4} \] ### Step 2: Multiply the entire inequality by -1 To eliminate the negative sign in front of the first term, we multiply the entire inequality by -1. Remember that when we multiply or divide an inequality by a negative number, we must reverse the inequality signs: \[ \frac{12}{5} > -6 + 9y > \frac{9}{4} \] ### Step 3: Rearrange the middle term Now, we can rearrange the middle term: \[ \frac{12}{5} > 9y - 6 > \frac{9}{4} \] ### Step 4: Add 6 to all parts of the inequality Next, we add 6 to all parts of the inequality: \[ \frac{12}{5} + 6 > 9y > \frac{9}{4} + 6 \] ### Step 5: Convert 6 to a fraction Convert 6 into a fraction with a denominator of 5: \[ 6 = \frac{30}{5} \] Now, adding: \[ \frac{12}{5} + \frac{30}{5} = \frac{42}{5} \] And for the right side: \[ \frac{9}{4} + 6 = \frac{9}{4} + \frac{24}{4} = \frac{33}{4} \] ### Step 6: Write the new inequality Now we have: \[ \frac{42}{5} > 9y > \frac{33}{4} \] ### Step 7: Divide the entire inequality by 9 Next, divide the entire inequality by 9 to isolate \(y\): \[ \frac{42}{5 \cdot 9} > y > \frac{33}{4 \cdot 9} \] Calculating the fractions: \[ \frac{42}{45} > y > \frac{33}{36} \] This simplifies to: \[ \frac{14}{15} > y > \frac{11}{12} \] ### Step 8: Find \(3y - 2\) Now, we need to find \(3y - 2\). We can multiply the entire inequality by 3: \[ 3 \cdot \frac{14}{15} > 3y > 3 \cdot \frac{11}{12} \] Calculating: \[ \frac{42}{15} > 3y > \frac{33}{12} \] This simplifies to: \[ 2.8 > 3y > 2.75 \] ### Step 9: Subtract 2 from all parts Now, subtract 2 from all parts of the inequality to find \(3y - 2\): \[ 2.8 - 2 > 3y - 2 > 2.75 - 2 \] This gives: \[ 0.8 > 3y - 2 > 0.75 \] ### Conclusion Thus, \(3y - 2\) lies between 0.75 and 0.8. A possible value for \(3y - 2\) is: \[ \boxed{0.76} \]
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