A certain 4 inch spring stretches 1.5 inches for each ounce of weight attached to it.

Answer

To solve the problem, we need to determine the final length of the spring when a certain weight is attached to it. We know the following:

1. The initial length of the spring is 4 inches.
2. The spring stretches 1.5 inches for each ounce of weight attached to it.

Let's denote the weight attached to the spring in ounces as \( x \).

### Step-by-Step Solution:

**Step 1: Identify the stretch of the spring based on the weight.**
- The stretch of the spring for \( x \) ounces of weight is given by the formula:
\[ \text{Stretch} = 1.5 \times x \]

**Step 2: Calculate the final length of the spring.**
- The final length of the spring can be calculated by adding the initial length of the spring to the stretch caused by the weight:
\[ \text{Final Length} = \text{Initial Length} + \text{Stretch} \]
- Substituting the values we have:
\[ \text{Final Length} = 4 + (1.5 \times x) \]

**Step 3: Write the final expression for the length of the spring.**
- Therefore, the final length of the spring as a function of the weight \( x \) is:
\[ \text{Final Length} = 4 + 1.5x \]

### Final Expression:
The final length of the spring when \( x \) ounces of weight is attached is given by:
\[ \text{Final Length} = 4 + 1.5x \]