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The average of a, b, c, d, and e is 28. ...

The average of a, b, c, d, and e is 28. If the average of a, c, and e is 24, what is the average of b and d?

A

`31`

B

`32`

C

`33`

D

`34`

Text Solution

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The correct Answer is:
To solve the problem step by step, we will follow the definitions of averages and manipulate the equations accordingly. ### Step 1: Understanding the average of a, b, c, d, and e The average of five numbers \( a, b, c, d, e \) is given as 28. The formula for average is: \[ \text{Average} = \frac{\text{Sum of values}}{\text{Number of values}} \] So, we can write: \[ \frac{a + b + c + d + e}{5} = 28 \] ### Step 2: Calculate the sum of a, b, c, d, and e To find the sum of \( a, b, c, d, e \), we multiply both sides of the equation by 5: \[ a + b + c + d + e = 28 \times 5 \] Calculating the right side: \[ a + b + c + d + e = 140 \] Let's call this **Equation 1**. ### Step 3: Understanding the average of a, c, and e Next, we know that the average of \( a, c, e \) is 24. Using the same average formula: \[ \frac{a + c + e}{3} = 24 \] ### Step 4: Calculate the sum of a, c, and e To find the sum of \( a, c, e \), we multiply both sides of the equation by 3: \[ a + c + e = 24 \times 3 \] Calculating the right side: \[ a + c + e = 72 \] Let's call this **Equation 2**. ### Step 5: Finding the sum of b and d Now, we want to find the sum of \( b \) and \( d \). We can do this by subtracting Equation 2 from Equation 1: \[ (a + b + c + d + e) - (a + c + e) = 140 - 72 \] This simplifies to: \[ b + d = 68 \] ### Step 6: Finding the average of b and d Now, we need to find the average of \( b \) and \( d \): \[ \text{Average of } b \text{ and } d = \frac{b + d}{2} \] Substituting the value we found for \( b + d \): \[ \text{Average of } b \text{ and } d = \frac{68}{2} = 34 \] ### Final Answer The average of \( b \) and \( d \) is **34**. ---
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