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The parabola whose equation is y=ax^(2)+...

The parabola whose equation is `y=ax^(2)+bx+c` passes through the points `(-3, -40), (0, 29), and (-1, 10)`. What is an equation of the line of symmetry?

A

`x=(17)/(4)`

B

`x=(9)/(2)`

C

`x=5`

D

`x=6`

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The correct Answer is:
To find the equation of the line of symmetry for the parabola given by the equation \( y = ax^2 + bx + c \) that passes through the points \((-3, -40)\), \((0, 29)\), and \((-1, 10)\), we will follow these steps: ### Step 1: Set up the equations using the given points We know that the points lie on the parabola, so we can substitute each point into the equation \( y = ax^2 + bx + c \) to form a system of equations. 1. For the point \((-3, -40)\): \[ -40 = a(-3)^2 + b(-3) + c \implies -40 = 9a - 3b + c \quad \text{(Equation 1)} \] 2. For the point \((0, 29)\): \[ 29 = a(0)^2 + b(0) + c \implies c = 29 \quad \text{(Equation 2)} \] 3. For the point \((-1, 10)\): \[ 10 = a(-1)^2 + b(-1) + c \implies 10 = a - b + c \quad \text{(Equation 3)} \] ### Step 2: Substitute \(c\) into the equations From Equation 2, we have \( c = 29 \). We can substitute this value into Equations 1 and 3. - Substituting into Equation 1: \[ -40 = 9a - 3b + 29 \implies 9a - 3b = -40 - 29 \implies 9a - 3b = -69 \] Dividing by 3: \[ 3a - b = -23 \quad \text{(Equation 4)} \] - Substituting into Equation 3: \[ 10 = a - b + 29 \implies a - b = 10 - 29 \implies a - b = -19 \quad \text{(Equation 5)} \] ### Step 3: Solve the system of equations Now we have a system of two equations (Equations 4 and 5): 1. \( 3a - b = -23 \) (Equation 4) 2. \( a - b = -19 \) (Equation 5) We can subtract Equation 5 from Equation 4: \[ (3a - b) - (a - b) = -23 - (-19) \] This simplifies to: \[ 3a - b - a + b = -23 + 19 \implies 2a = -4 \implies a = -2 \] ### Step 4: Find \(b\) Now substitute \( a = -2 \) back into Equation 5: \[ -2 - b = -19 \implies -b = -19 + 2 \implies -b = -17 \implies b = 17 \] ### Step 5: Find the line of symmetry The equation of the line of symmetry of a parabola given by \( y = ax^2 + bx + c \) is given by: \[ x = -\frac{b}{2a} \] Substituting the values of \( a \) and \( b \): \[ x = -\frac{17}{2(-2)} = \frac{17}{4} \] ### Final Answer The equation of the line of symmetry is: \[ \boxed{x = \frac{17}{4}} \]
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