To find the area of trapezoid ABCD, use the fact that the lengths of the sides of right triangle AEB form a (5-12-13) Pythagorean triple, where height `BE=12`. The length of lower base `AD=AE+ED=5+5+27=32`

To find the area of triangleABC , note that the lengths of the sides of triangleABC form (3-4-5) Pythagorean triple, where AC=4 . Hence, Find the area of triangleABC .

To find the area of trapezoid ABCD, first the length of base CD by drawing heigth BH to CD. Since parallel lines are everywhere equidistant, BH=AD=15 . The lengths of the sides of right triangle BHC from an (8-15-17) Pythagorean triple, where CH=8. Thus, CD=CH+HD=8+10=18 .

Find the area of an isosceles triangle having the base 6 cm and the length of each equal side 5 cm.

The lengths of the sides of a triangle are in the ratio 4:5:3 and its perimeter is 96 cm. Find its area.

The lengths of the sides of a triangle are in the ratio 4 : 5 : 3 and its perimeter is 96 cm. Find its area.

Find the lengths of the sides of the triangle whose vertices are A(2,4,-1),(4,5,1),C(3,6,-3) and show that the triangle is right angled.

To find the area of rectangle ABCD, note that the diagonal form a (5-12-13) right triangle so the width of the rectangle is 5. Hence,Find area of triangle.:

Find the length of the diagonal of a rectangle whose sides are 12cm and 5cm.

The hypotenuse of a right triangle is 13cm long. If one of the remaining two sides is of length 5cm, find the length of another side.

The length of the sides of a triangle are in the ratio 3 : 4 : 5 . Find the area of the triangle if its perimeter is 144 cm.