To find the area of trapezoid ABCD, first the length of base CD by drawing heigth BH to CD. Since parallel lines are everywhere equidistant, `BH=AD=15`. The lengths of the sides of right triangle BHC from an (8-15-17) Pythagorean triple, where CH=8. Thus, `CD=CH+HD=8+10=18`.

To find the area of trapezoid ABCD, use the fact that the lengths of the sides of right triangle AEB form a (5-12-13) Pythagorean triple, where height BE=12 . The length of lower base AD=AE+ED=5+5+27=32

Find the area of a triangle : whose three sides are 17 cm, 8 cm and 15 cm long. Also, in part (ii) of the question, calculate the length of the altitude corresponding to the largest side of the triangle.

Find the area of triangle whose sides are 17 cm, 8 cm and 15 cm. Also calculate the length of the altitude corresponding to the largest side of the triangle.

The given figure shows a trapezium ABCD in which AB = 17 cm, BC = 8 cm and CD = 15 cm. Find the area and perimeter of the trapezium.

In Figure 3, a circle touches all the four sides of a quadrilateral ABCD whose sides are AB = 6 cm, BC = 9 cm and CD = 8 cm. Find the length of side AD.

Length of the fence of a trapezium shaped field ABCD is 120 m. If BC=48m, CD=17m and AD=40m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC.

Length of the fence of a trapezium shaped field ABCD is 120 m. If BC=48m, CD=17m and AD=40m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC.

The dimensions of a rectangle ABCD are "51 cm" xx "15 cm". A trapezium PQCD with its parallel sides QC and PD in the ratio 9:8, is cut off from the rectangle as shown in the figure. If the area of the trapezium PQCD is (5)/(6) th part of the area of the rectangle. Find the length QC and PD.

A rectangular coil ABCD is hung from one side of a balance as shown in higure. A 500 g mass is added to the other arm to balance the weight of the coil. A current of 9.8 A is passed through the coil and a constant magnetic field of 0.4 T acting inward (in xz plane) is switched on such that only arm CD of length 1.5 cm lies in the field. The additional mass m must be added to regain the balance is

Find the area of the given figure Given AB = 18 cm, BC = 7 cm, CD = 20 cm, DE = 8 cm, EA = 17 cm, AF = 30 cm, BF = 24 cm, CF = 25 cm, FD = 15 cm, EF = 17 cm.