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When a base ball by a batter, the height...

When a base ball by a batter, the height of the ball, h(t), at time t, is determined by the equation `h(t)=-16t^(2)+64t+4`, where `tge0`. For which interval of time, in seconds, is the height of the ball at least 52 feet above the playing field?

A

`0.5letle2.5`

B

`1.0letle3.0`

C

`1.5letle3.5`

D

`2.0letle4.0`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the interval of time \( t \) during which the height of the baseball \( h(t) \) is at least 52 feet. The height of the baseball is given by the equation: \[ h(t) = -16t^2 + 64t + 4 \] We need to find when \( h(t) \geq 52 \). ### Step 1: Set up the inequality We start by setting up the inequality: \[ -16t^2 + 64t + 4 \geq 52 \] ### Step 2: Rearrange the inequality Next, we rearrange the inequality by subtracting 52 from both sides: \[ -16t^2 + 64t + 4 - 52 \geq 0 \] This simplifies to: \[ -16t^2 + 64t - 48 \geq 0 \] ### Step 3: Factor out common terms We can factor out -16 from the left side: \[ -16(t^2 - 4t + 3) \geq 0 \] Dividing the entire inequality by -16 (and remembering to reverse the inequality sign): \[ t^2 - 4t + 3 \leq 0 \] ### Step 4: Factor the quadratic expression Now, we factor the quadratic expression: \[ (t - 1)(t - 3) \leq 0 \] ### Step 5: Determine the critical points The critical points from the factors are \( t = 1 \) and \( t = 3 \). ### Step 6: Test intervals We will test the intervals determined by the critical points: 1. **Interval 1**: \( t < 1 \) (e.g., \( t = 0 \)): \[ (0 - 1)(0 - 3) = ( -1)( -3) = 3 > 0 \] 2. **Interval 2**: \( 1 < t < 3 \) (e.g., \( t = 2 \)): \[ (2 - 1)(2 - 3) = (1)(-1) = -1 < 0 \] 3. **Interval 3**: \( t > 3 \) (e.g., \( t = 4 \)): \[ (4 - 1)(4 - 3) = (3)(1) = 3 > 0 \] ### Step 7: Conclusion of intervals The inequality \( (t - 1)(t - 3) \leq 0 \) holds true in the interval: \[ 1 \leq t \leq 3 \] Thus, the height of the ball is at least 52 feet during the interval \( [1, 3] \). ### Final Answer The interval of time in seconds during which the height of the ball is at least 52 feet is: \[ \text{Option B: } 1 \leq t \leq 3 \]
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