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SUBHASH PUBLICATION-TRIGONOMETRY-Prove the following
- (sin x - sin 3x)/(sin^(2)x-cos^(2)x)=2sinx
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- (cos 4x+cos3x+cos2x)/(sin 4x+sin3x+sin2x)=cot3x
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- cot x cot 2x-cot 2x cot3x-cot3x cotx=1
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- tan4x=(4tan x(1-tan^(2)x))/(1-6tan^(2)x+tan^(4)x)
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- Prove that : tan 3x=(3tanx-tan^(3)x)/(1-3tan^(2)x)
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- Prove that: (tan theta)/(1-cot theta)+(cot theta)/(1-tan theta)=1+sec ...
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- (tan theta+sec theta-1)/(tan theta-sec theta+1)=(1+sin theta)/(cos the...
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- If 2 sin^(2) theta +5 cos theta=4, Prove that cos theta=1//2
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- If sec theta=13//5 and theta is acute find (2 sin theta-3 cos theta)/(...
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- Show that : tan 3x tan 2x tan x =tan 3x-tan2x-tanx
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- Prove that : cos((pi)/4+x)+cos((pi)/4-x)=sqrt(2)cosx
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- Prove that =(sin 5x-2sin3x+sinx)/(cos5x-cosx)=tanx
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- sin(A+B).sin(A- B)=sin^(2)A-sin^(2)B
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- cos (A+B).cos(A-B)=cos^(2)A-sin^(2)B
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- tan((pi)/4+A)=(1+tanA)/(1-tanA)
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- tan((pi)/4-A)=(1-tanA)/(1+tanA)
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- cot(A-B)=(cotA.cotB+1)/(cotB-cotA)
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- cot(A-B)=(cotA.cotB+1)/(cotB-cotA)
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- If sinA=3//5,cosB=5//13 & A,B are acute, find sin(A+B)
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- If sinA=4/5,cosB=(-12)/13 and (pi)/2ltA,Bltpi , Find sin(A-B)
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