In YDSE setup a light of wavelength `6000Å` is used. What should be the separation between the slits so that on screen in front of one of the slit there will be third bright fringe. Take D = 1m.
`[0.6sqrt(10)mm]`

Two slits, 4 mm apart, are illuminated by light of wavelength 6000 Å . What will be the fringe width on a screen placed 2 m from the slits

Young’s double slit experiment is performed with light of wavelength 550 nm . The separation between the slits is 1.10 mm and screen is placed at distance of 1 m . What is the distance between the consecutive bright or dark fringes

In a YDSE green light of wavelength 500 nm is used. Where will be the second bright fringe be formed for a set up in which separation between slits is 4 mm and the screen is placed 1 m from the slits?

In a YDSE setup sodium light of wavelength 5893 Å is being used. The interference pattern is obtained on a screen which is located at a distance 1 m from the slit plane. In the interference pattern it is observed that 10^(th) bright fringe is located at a distance of 12mm from the central maximum. Find the slit separation.

In a Y.D.S.E, light of wavelength 500 nm is used. The separation between bright fringes is 7.5 mm., calculate the fringe width if light is replaced by another light of wavelength 650 nm and separation between the slits is increased to 1.5 times.

In a double experiment, the distance between the slit is 1 mm and screen is 25 cm away from the slits. The wavelength of light is 6000Å . The width of the fringe on the screen is

In Young's double slit experiment, slit separation is 0.6 mm and the separation between slit and screen is 1.2m . The angular width is (the wavelength of light used is 4800Å )