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In a single slit diffraction pattern the...

In a single slit diffraction pattern the angular width of a central maxima is `30^(@)`. When the slit is illuminated by light of wavelength `6000Å`. Then width of the slit will be approximately given as :

A

`12 xx 10^(-6)m`

B

`12 xx 10^(-7)m`

C

`12 xx 10^(-8)m`

D

`12 xx 10^(-9)m`

Text Solution

Verified by Experts

The correct Answer is:
B
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Knowledge Check

  • In a single slit diffraction pattern intensity and width of fringes are

    A
    unequal width
    B
    equal width
    C
    equal width and equal intensity
    D
    unequal width and unequal intensity

  • Angular width of central maxima is pi//2 , when a slit of width 'a' is illuminated by a light of wavelength 7000 Å then a =

    A
    `9xx10^(-9)m`
    B
    `8.0xx10^(-7)m`
    C
    `9xx10^(-7)m`
    D
    `9.8xx10^(-7)m`

  • A slit of worth 12 times 10^-7 m is illuminated by light of wavelength 6000A. The angular width of the central maximum is approximately-

    A
    `30^@`
    B
    `60^@`
    C
    `90^@`
    D
    `0^@`

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    In a single slit diffraction pattern, how does the angular width of central maxima change when light of smaller visible wavelength is used ? Justify your answer.

    What will be the angular width of central maxima in Fraunhofer diffraction when light of wavelength 6000Å is used and slit width is 12xx10^-5cm ?

    What will be the angular width of central maxima in Franuhoffer diffraction when light of wavelength 12000 nm falls on slit of width 5mm ?

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