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The distance between two slits in a YDSE...

The distance between two slits in a YDSE apparatus is 3mm. The distance of the screen from the slits is 1m. Microwaves of wavelength 1 mm are incident on the plane of the slits normally. Find the distance of the first maxima on the screen from the central maxima.

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The correct Answer is:
[35.35cm app.,5]
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PHYSICS GALAXY - ASHISH ARORA-WAVE OPTICS-Unsolved Numerical Problems
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  2. Light of wavelength 520nm passing through a double slit,produced inter...

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  3. The distance between two slits in a YDSE apparatus is 3mm. The distanc...

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  4. One radio transmitter A operating 60.0MHzis 10.0from another similar t...

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  5. The central fringe of the interference pattern produced by the light o...

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  6. A broad sources of light of wavelength 680nm illuminated normally two ...

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  7. Two microwave coherent point sources emitting waves of wavelenths lamb...

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  8. In a YDSE two thin transparent sheet are used in front of the slits S(...

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  9. In a two slit experiment with monochromatic light fringes are obtained...

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  10. A source S is kept directly behind the slit S(1) in a double slit appa...

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  11. In a YDSE a parallel beam of light of wavelength 6000Å is incident on ...

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  12. A plastic film with index of refraction 1.80 is put on the surface of ...

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  13. Two coherent monochromatic sources A and B emit light of wavelength la...

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  14. A beam of light consisting of two wavelength, 6500 Å and 5200 Å is use...

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  15. In an experiment using Fresnel biprism, fringes of width 0.185 xx 10^(...

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  16. Two identical monochromaticlight sources A & B intensity 10^(-15)W//m^...

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  17. Two fine slits are placed very close to each other and they are illumi...

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  18. Biprism fringes are produced with the help of sodium light (lambda=589...

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  19. A glass plate 1.2 xx 10^(-6)m thick is placed in the path of one of th...

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  20. A narrow monochromatic beam of light of intensity 1 is incident on a g...

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