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In a YDSE a parallel beam of light of wa...


In a YDSE a parallel beam of light of wavelength 6000Å is incident on slits at angle of incidence `30^(@)`. A and B are two thin transparent films each of refractive index 1.5. thickness of A is `20.4mum`. Light coming through A and B have intensities I and 4I resepctively on the screen. Intensity at point O which is symmetric relative to the slits is 3I. The central maxima is above O.
(i). what is the maximum thickness of B to do so. Assuming thickness of B to be that found in part (i) answer the following parts.
(ii). Find fringe width, maximum intensity and minimum intensity on screen.
(iii). Dinstance of nearest minima from O
(iv) intensity at 5 cm on either side of O.

A

What is the maximum thickness of B to do so ? Assuming thickness of B to be that found in part (a) answer the followimg parts :

B

Find fringe width, maximum intensity & minimum intensity on screen.

C

Distance of nearest minima from O.

D

Intensity at 5 cm on either side of O.

Text Solution

Verified by Experts

The correct Answer is:
`[(a)t_(B)=120mu m; (b) beta=6mm;I_("max")=9I,I_("min")=I;(c )beta//6=1mm (d) I (at5 cm " above "0)=9I]`
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