[" 21."x+2y=0],[" 2"x+ky=5]

Find the value of k for which the following system of equation has no solution: x+2y=0,quad 2x+ky=5

If the lines 2x+ y-3 = 0, 5x+ky - 3=0 and 3x -y -2 =0 are concurrent, find the value of k.

Consider the lines give by L_1: x+3y -5=0, L_2:3x - ky-1=0, L_3: 5x +2y -12=0

If the lines 2x + y - 3 = 0 , 5x + ky - 3 = 0 " and " 3x - y - 2 = 0 are concurrent , find the value of k.

If the lines 2x + y - 3 = 0 , 5x + ky - 3 = 0 " and " 3x - y - 2 = 0 are concurrent , find the value of k.

If the lines 2x + y - 3 = 0 , 5x + ky - 3 = 0 " and " 3x - y - 2 = 0 are concurrent , find the value of k.

5x - 7 y - 5 =0 , 2x + ky - 1 =0

If the lines given by 3x+ 2ky =2 and 2x+ 5y+1= 0 are parallel, then the value of k is