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Photons of wavelength lambda are inciden...

Photons of wavelength `lambda` are incident on a metal. The most energetic electrons ejected from the metal are bent into a circular arc of radius R by a perpendicular magnetic field having a magnitude B. The work function of the metal is (Where symbols have their usual meanings) -

A

`(hc)/(lambda)-m_(e)+(e^(2)B^(2)R^(2))/(2m_(e))`

B

`(hc)/(lambda)+2m_(e)((eBR)/(2m_(e)))^(2)`

C

`(hc)/(lambda)-m_(e)C^(2)-(e^(2)B^(2)R^(2))/(2m_(e))`

D

`(hc)/(lambda)-2m_(e)((eBR)/(2m_(e)))^(2)`

Text Solution

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The correct Answer is:
D
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