[" Q.Let "f(x)=x^(2)" and "g(x)=2^(x)" then "],[" 27the solution set of "fog(x)=gof(x)" is "]

Let f(x)=x^2 and g(x)=2^x . Then the solution set of the equation fog(x)=gof(x) is R (b) {0} (c) {0, 2} (d) none of these

Let f(x)=x^2 and g(x)=2^x . Then the solution set of the equation fog(x)=gof(x) is (a)R (b) {0} (c) {0, 2} (d) none of these

Let f(x) = x^(2), g(x) = 2^(x) . Then solve the equation (fog)(x)=(gof)(x) .

If f(x)=4x^(2) and g(x)=x^(1/2) then find gof and fog.

Let f(x) = [x] and g(x) = |x| then find the value of (fog)(1/2) - (gof) (1/2)

If f(x)=x^(2),g(x)=2^x and (fog)(x)=(gof)(x), then the values of x are

If f(x)=x^(2),g(x)=2^x and (fog)(x)=(gof)(x) , then the values of x are

Let f(x)=x^2+x+1 and g(x)=sinx . Show that fog!=gof .

Let f(x)=x^2+x+1 and g(x)=sinx . Show that fog!=gof .