" ờ "y=sqrt(((x-a)(x-b))/((x-c)(x-d)))," dì "(dy)/(dx)=

If y = sqrt(((x-a)(x-b))/((x-c)(x-d))), " then " (dy)/(dx) is equal to

Find (dy)/(dx) when : y=sqrt(((x-a)(x-b))/((x-c)(x-d)))

if y=((a-x)sqrt(a-x)-(b-x)sqrt(x-b))/(sqrt(a-x+sqrt(x-b)))," then "(dy)/(dx) wherever it is defined is

sqrt((y)/( x))+ sqrt((x)/(y))= 2 implies (dy)/(dx) =

If sqrt((y)/(x))+sqrt((x)/(y))=6, then (dy)/(dx) is

If y = Arc tan sqrt([(x -a)/(b -x)]) then (dy)/(dx) =

If y=sqrt(x)+(1)/(sqrt(x)) , then (dy)/(dx) at x=1 is

if y=((a-x)sqrt(a-x)-(b-x)sqrt(x-b))/(sqrt(a-x)+sqrt(x-b)) then (dy)/(dx) wherever it is defined is equal to

If y=sqrt(x+sqrt(x+sqrt(x.." to "oo)))," then "(dy)/(dx)=