" (i) "(DP)/(PL)=(DC)/(BL)

ABCD is a parallelogram.P is a point on the side BC DP when produced meets AB produced at .Prove that (DP)/(PL)=(DC)/(BL) (ii) (DL)/(DP)=(AL)/(DC)

((dG)/(dp))_(T)=

((dG)/(dp))_(T)=

P is a point on side BC of a parallelogram ABCD. If DP produced meets AB produced at point L, prove that : DP : PL = DC : BL .

BL and CM are medians of DeltaABC , right - angled a A. Prove that 4("BL"^(2)+"CM"^(2))=5" BC"^(2)

BL and CM are medians of a triangle ABC right angled at A. Prove that 4(BL^(2)+ CM^(2))=5BC^(2)

For a gaseous reaction, A(g)rarr Products, which one of the following is correct relation among (dp)/(dt),(dn)/(t) and (dc)/(dt) ? ( (dt)/(dt) = Rate of reaction in atm "sec"^(-1),(dc)/(dt) = Rate reaction in molarity "sec"^(-1),(dn)/(dt) = Rate of reaction in mol "sec"^(-1) )

ABCD is a parallelogram in which angleDAB=80^(@) . Bisector of angleA and angleB meets CD at P. Prove that : (i) AD = DP (ii) CP = CB (iii) DC = 2AD

In a right tringle ABC, right-angled at B, D is a point on hypotenuse such that BD bot AC . If DP bot AB and DQ bot BC then prove that (a) DQ^(2)=DP*QC" " DP^(2)=DQ*AP .