Under a fore (10hati-3hatj+6hatk) newton...

Under a fore `(10hati-3hatj+6hatk)` newton a bod of mass 5 kg moves from position `(6hati+5hatj-3hatk)` m to position `(10hati-2hatj+7hatk)`m. deduce the work done.

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Under a force ( 10 hati - 3 hatj + 6 hatk) newton a body of mass 5 kg moves from position ( 6 hati + 5 hatj - 3 hatk) m to position ( 10 hati - 2hatj+ 7hatk) m . Deduce the work done.

Under a force of 10 hati - 3 hatj +6 hatk newton, a body of mass 5 kg is displaced from the position 6 hati + 5 hatj - 3 hatk to the position 10 hati - 2hatj + 7 hatk . Calculate the work done.

Under the effect of a force vecF=5hati-2 hatj+3hatk N, abody of mass 1 kg is displaced from position 5hati+4hatj-2hatk to position 8hati-hatj-hat4k . Calculate the work done .

A constant force vecF=(3hati+2hatj+2hatk) N acts on a particle displacing it from a position vec(r_1)=(-hati+hatj-2hatk)m to a new position vecr_2=(hati-hatj+3hatk)m . Find the work done by the force.

Two constant forces F_(1)=2hati-3hatj+3hatk(N) and F_(2)=hati+hatj-2hatk(N) act on a body and displace it from the position r_(1)=hati+2hatj-2hatk(m) to the position r_(2)=7hati+10hatj+5hatk(m) . What is the work done

A force vecF=(2hati+3hatj+4hatk)N displaces a body from position vector vec(r_(1))=(2hati+3hatj+hatk)m to the positive vector vec(r_(2))=(hati+hatj+hatk)m . Find the work done by this force.

Find the projection of hati+3hatj+7hatk on the vector 2hati-3hatj+6hatk

Calculate the work done by a force F = -5hati+hatj+7hatk N when its point of application moves from point (-2hati-6hatj+hatk)m to the point (hati-hatj+10hatk)m .

A constant force of (2hati+3hatj+5hatk) N produces a displacement of (3hati+2hatj+2hatk) m. Then work done is

ANURAG MISHRA-DESCRIPTION OF MOTION-Example

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Under a fore (10hati-3hatj+6hatk) newton a bod of mass 5 kg moves from...
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