Differentiate
(a). `f(x)=(1)/(x^(2))`
(b). `y=root2(x^(2))`

differentiate y=(x+(1)/(x))^((1)/(2))

Differentiate f(x) = (x+2)^(2/3) (1-x)^(1/3) w.r.t. x

Differentiate y=log(x+sqrt(x^2+1))

If y =int _(u(x))^(v(x))f(t) dt , let us define (dy)/(dx) in a different manner as (dy)/(dx) = v'(x) f^(2)(v(x)) - u'(x) f^(2)(u(x)) alnd the equation of the tangent at (a,b) as y -b = (dy/dx)_((a,b)) (x-a) If F(x) = int_(1)^(x)e^(t^(2)//2)(1-t^(2))dt , then d/(dx) F(x) at x = 1 is

Differentiation OF term F(xy) +Y.y(x.y)

If (d)/(dx)[f(x)]=(1)/(1+x^(2))," then: "(d)/(dx)[f(x^(3))]=

If f(x) and g(x) are two solutions of the differential equation (a(d^(2)y)/(dx^(2))+x^(2)(dy)/(dx)+y=e^(x),thenf(x)-g(x)^(@) is the solution of

If (d(f(x))/(dx)=(1)/(1+x^(2)) then (d)/(dx){f(x^(3))} is

Let f(x) be a differentiable and let c a be a constant.Then cf(x) is also differentiable such that (d)/(dx){cf(x)}=c(d)/(dx)(f(x))