Home
Class 11
PHYSICS
Let s(t)=t^(3)-6t^(2) be the position fu...

Let `s(t)=t^(3)-6t^(2)` be the position function of a particle moving along an s-axis, where s is in meters and t is in sec. find the instantaneous acceleration a(t) and show the graph of acceleration versus time.

Promotional Banner

Topper's Solved these Questions

  • DESCRIPTION OF MOTION

    ANURAG MISHRA|Exercise Level-1|86 Videos
  • DESCRIPTION OF MOTION

    ANURAG MISHRA|Exercise Level-2|25 Videos
  • DESCRIPTION OF MOTION

    ANURAG MISHRA|Exercise Level-3|34 Videos
  • FORCE ANALYSIS

    ANURAG MISHRA|Exercise Matching type|13 Videos

Similar Questions

Explore conceptually related problems

The position (x) of a particle moving along x - axis veries with time (t) as shown in figure. The average acceleration of particle in time interval t = 0 to t = 8 s is

The displacement of a particle moving in a straight line, is given by s = 2t^2 + 2t + 4 where s is in metres and t in seconds. The acceleration of the particle is.

The position of a particle is given by the equation f(t)=t^(3)-6t^(2)+9t where t is measured in second and s in meter. Find the acceleration at time t. What is the acceleration at 4 s?

The displacement of a particle moving along an x axis is given by x=18t+5.0t^(2) , where x is in meters and t is in seconds. Calculate (a) the instantaneous velocity at t=2.0s and (b) the average velocity between t=2.0s and t=3.0s .

A particle is moving along the x-axis such that s=6t-t^(2) , where s in meters and t is in second. Find the displacement and distance traveled by the particle during time interval t=0 to t=5 s .

A particle is moving such that s=t^(3)-6t^(2)+18t+9 , where s is in meters and t is in meters and t is in seconds. Find the minimum velocity attained by the particle.

The equation of motion of a particle moving along a straight line is s=2t^(3)-9t^(2)+12t , where the units of s and t are centrimetre and second. The acceleration of the particle will be zero after

The velocity of a particle is given by v=(2t^(2)-3t+10)ms^(-1) . Find the instantaneous acceleration at t = 5 s.

ANURAG MISHRA-DESCRIPTION OF MOTION-Example
  1. find the derivative of the function g(t)=((t-2)/(2t+1))^(9)

    Text Solution

    |

  2. Defferentiate y=e^(sinx)

    Text Solution

    |

  3. Let s(t)=t^(3)-6t^(2) be the position function of a particle moving al...

    Text Solution

    |

  4. The po9sition of aparticle is given by the equation. s=f(t)=t^(3)-6t...

    Text Solution

    |

  5. sketh the region whose area is represented by the definite integral an...

    Text Solution

    |

  6. Evaluate (a). int(0)^(2)(x-1)dx (b). underset(0)overset(2)(x-1)dx

    Text Solution

    |

  7. (a). Find the area under the curve y=cosx over the interval [0,pi//2] ...

    Text Solution

    |

  8. Evaluate int(0)^(3)(x^(3)-6x)dx

    Text Solution

    |

  9. Find int(0)^(2)(2x^(3)-6x+(3)/(x^(2)+1))dx

    Text Solution

    |

  10. Evaluate underset(1)overset(9) ((2t^(2)+t^(1/2)sqrt(t)-1)/(t^2)dt)

    Text Solution

    |

  11. A particle moves along a line so that its velocity at time t is v(t)...

    Text Solution

    |

  12. Find the position function of a particle that moves with velocity v(t)...

    Text Solution

    |

  13. Suppose that a particle mvoes on a straight line so that is velocity a...

    Text Solution

    |

  14. Fig. shows thre velocity versus time curves for a particle in rectilin...

    Text Solution

    |

  15. find the total area between the cuve y=1-x^(2) and the x-axis over the...

    Text Solution

    |

  16. A bicycle moves along a stragith road such that its construct the v-t ...

    Text Solution

    |

  17. An experimental car in fig (a) starts from rest and travels along a st...

    Text Solution

    |

  18. Given a=4-2t, initial velocity at t=0,u=5, find distance travelled til...

    Text Solution

    |

  19. If a particle with a = kv^(2) and initial velocity is u then velocity ...

    Text Solution

    |

  20. Given a=-cost, at t=0,u=0,x=1 Position at t=pi Find distance from ...

    Text Solution

    |