Home
Class 11
PHYSICS
(i) A particle is moving in three dimens...

(i) A particle is moving in three dimensions.Its position vector is given by
`vecr=6hati+(3+4t)hatj-(3+2t-t^(2))hatk`
Distance are in meters, and the time t, in seconds.
( a) What is the velocity vector at `t = + 3 ?`
(b) What is the speed `("in" m//"sec") at. t = + 3` ?
(c) What is the acceleration vector and what is its magnitude `("in m"//"sec"^(2)) at.t = +3`?
(ii) Now the particle is moving only along the z-axis, and its position is given by `(t^(2)- 2t -3)hatk` k at what time does the particle stand still? _

Promotional Banner

Topper's Solved these Questions

  • DESCRIPTION OF MOTION

    ANURAG MISHRA|Exercise Level-1|86 Videos

  • DESCRIPTION OF MOTION

    ANURAG MISHRA|Exercise Level-2|25 Videos

  • DESCRIPTION OF MOTION

    ANURAG MISHRA|Exercise Level-3|34 Videos

  • FORCE ANALYSIS

    ANURAG MISHRA|Exercise Matching type|13 Videos

Similar Questions

Explore conceptually related problems

A particle moves on the xy-pane such that its position vector is given by vec(r)=3t^(2) hati-t^(3) hatj . The equation of trajectory of the particle is given by

The position of a particle is given by vec r =(8 t hati +3t^(2) hatj +5 hatk) m where t is measured in second and vec r in meter. Calculate, direction of the velocity at t = 1 s

If the velocity of the a particle moving on x-axis is given by v=3t^(2)-12 t +6. at what time is the acceleration of particle zero ?

The position vector of a particle is given by vecr=(2 sin 2t)hati+(3+ cos 2t)hatj+(8t)hatk . Determine its velocity and acceleration at t=pi//3 .

A particle is moving with uniform acceleration. Its position (x) is given in term of time (t in sec) as x= '(5t^2 +4t +8)' m, then

If the position vector of a particle is given by vec r =(4 cos 2t) hat j + (6t) hat k m , calculate its acceleration at t=pi//4 second .

The position of a particle is given by vec r =(8 t hati +3t^(2) +5 hatk) m where t is measured in second and vec r in meter. Calculate, the magnitude of velocity at t = 5 s,

The position of an object is given by vecr= ( 9 thati + 4t^(3)hatj) m. find its velocity at time t= 1s.

A particle moves in xy-plane. The position vector of particle at any time is vecr={(2t)hati+(2t^(2))hatj}m. The rate of change of theta at time t = 2 second. ( where 0 is the angle which its velocity vector makes with positive x-axis) is :

The position of a particle is given by the equation f(t)=t^(3)-6t^(2)+9t where t is measured in second and s in meter. Find the acceleration at time t. What is the acceleration at 4 s?

ANURAG MISHRA-DESCRIPTION OF MOTION-Example
  1. A particle having a velocity v = v0 at t= 0 is decelerated at the rate...

    Text Solution

    |

  2. A particle travels so that its acceleration is given by vec(a)=5 cos t...

    Text Solution

    |

  3. (i) A particle is moving in three dimensions.Its position vector is gi...

    Text Solution

    |

  4. A body projected vertically upward from the top of a tower reaches the...

    Text Solution

    |

  5. A body falls from same height and return back to initial position Draw...

    Text Solution

    |

  6. A boy throws a ball vertically upward with an initial speed of 15.0m//...

    Text Solution

    |

  7. A man standing in an elevator observes a screw fall from the ceiling. ...

    Text Solution

    |

  8. A speeder moves at a constant 15m//s in a school zone A police car sta...

    Text Solution

    |

  9. two cars approach each other on a straight road. Car A moves at 16 m//...

    Text Solution

    |

  10. A circular wire frame is fixed in a vertical plane. A smooth wire is t...

    Text Solution

    |

  11. A car is speeding at 25 m//s in a low speed zone .A police car starts ...

    Text Solution

    |

  12. Ball 1 is released from the top of a smooth inclined plane, the at the...

    Text Solution

    |

  13. The velocity of a particle at t=0 "is"vecU = 4hati+3hatj"m"//"sec" and...

    Text Solution

    |

  14. The acceleration of a moving body at any time 't' is given by veca=(4t...

    Text Solution

    |

  15. A particle of mass 1 kg has a velocity of 2m//s. A constant force of 2...

    Text Solution

    |

  16. A particle is moving in xy-plane .At certain instant the components of...

    Text Solution

    |

  17. The figure shows the velocity and the accelerationl of a point-like bo...

    Text Solution

    |

  18. A footballer throws a ball from a height of 2.00m above the ground wit...

    Text Solution

    |

  19. A bomber is moving horizontally at a speed v(1)=72m//s at a height of ...

    Text Solution

    |

  20. A boy throws a ball with velocity v(0) =10sqrt2 m//s at an angle of 45...

    Text Solution

    |