A boy throws a ball vertically upward with an initial speed of `15.0m//s`.The ball was released when it was at `2.00`m above ground. The boy catches it at the same point as the point of projection
(a) What is maximum height reaches by the ball ?
How long is the ball in the air?

A ball is thrown from the top of a tower in vertically upward direction. Velocity at a point h m below the point of projection is twice of the velocity at a point h m above the point of projection. Find the maximum height reached by the ball above the top of tower.

A body throws a ball from shoulder height at an initial velocity of 30 m/s. Spending 4.8 s in air, the ball is caught by another boy as the same shoulder-height level. What is the angle of projection ?

A ball is thrown up at a speed of 4.0 m/s. Find the maximum height reached by the ball. Take g=10 m//s^2 .

A ball is thrown vertically upward with a velocity of 20 m/s. Calculate the maximum height attain by the ball.

A ball is projected vertically up with an initial speed of 20m//s on a planet where acceleration due to gravity is 10m//s^(2) (a) How long does it takes to reach the highest point? (b) How high does it rise above the point of projection? (c) How long wil it take for the ball to reach a point 10m above the point of projection?

A player throws a ball upwards with an initial speed of 30 m s^(-1) . How long does the ball take to return to the player's hands? ( Take g = 10 m s^(-2) )

A football player kicks a ball at ball at an angle of 30 ^(0) with the horizontal with an initial speed of 20 m//s . Assuming that the ball travels in a vertical plance, calculate (a) the time at which the ball reaches the highest point (b) maximum height reached (c ) the horizontal range of the ball (d) the time for which the ball is in air. g =10 m//s^(2) .

A ball is throw vertically upward. It has a speed of 10 m//s when it has reached on half of its maximum height. How high does the ball rise ? (Taking g = 10 m//s^2 ).

Soumya throws a ball upwards, from a rooftop, 80 m above. It will reach a maximum height and then fall back to the ground. The height of the ball from the ground at time 't' is 'h', which is given by h=-16t^(2)+64t+80 What is the maximum height reached by the ball ?

A ball is projected vertically upwards with a certain initial speed. Another ball of the same mass is projected at an angle of 60^(@) with the vertical with the same initial speed. At highest points of their journey, the ratio of their potential energies will be