A speeder moves at a constant `15m//s` in a school zone A police car starts from rest just as the speeder passed it.The police car accelerates at.`2 m//s^(2)` until it reaches its.maximum velocity of `20 m//s.`Where and when does the speeder get caught ?

A car is speeding at 25 m//s in a low speed zone .A police car starts from rest just as the speeder passes and accelerates at a constant rate of 5m//s^(2) (a) When does the police car catch the speeding car? (b) How fast in the police car travelling when it catches up with the speeder ? How for have the cars travelled when the police car catches the speeder?

A car accelerates uniformly at 4 m s^(-2) from rest. Find its velocity at the end of 5 seconds.

A car acceletrates uniformaly at 4 m s^(-2) froms rest. Find its velocity at the end of 5 seconds.

A body starts from rest with an acceleration 2m//s^(2) till it attains the maximum velocity then retards to rest with 3m//s^(2) . If total time taken is 10 second, then maximum speed attained is

An object starts from rest at the origin and moves along the x axis with a constant acceleration of 4m//s^(2) . Its average velocity as it goes from x=2 m to x=8 m is :

A car starts from rest and moves with uniform acceleration of 5 m//s^(2) for 8 sec. If the acceleration ceases after 8 seconds then find the distance covered in 12s starting from rest.

Car A starts from a point O and moves with constant velocity 9 m//s . After 2 s , another car B begins its journey from O and follows car A . If car B starts from rest and moves under constant acceleration 4 m//s^(2) , after how much time and at what distance from O the cars meet?

A car acceleration from rest at a constant rate 2m//s^(2) for some time. Then, it retards at a constant rate of 4 m//s^(2) and comes to rest. If it remains motion for 3 second, then the maximum speed attained by the car is:-