The velocity of a particle at `t=0 "is"vecU = 4hati+3hatj"m"//"sec"` and a constant acceleration is `veca=6hati+4hatj"m"//"sec"^(2)`. Find the velocity and displacement of the particle at `t=2 sec.`

The velocity of an object at t =0 is vecv_(0) =- 4 hatj m/s . It moves in plane with constant acceleration veca = ( 3hati + 8 hatj) m//s^(2) . What is its velocity after 1 s?

Velocity and acceleration of a particle at time t=0 are u=(2 hati+3 hatj) m//s and a=(4 hati+3 hatj) m//s^2 respectively. Find the velocity and displacement if particle at t=2s.

A particle is given an initial velocity of vecu=(3 hati+4 hatj) m//s . Acceleration of the particle is veca=(3t^(2) +2 thatj) m//s^(2) . Find the velocity of particle at t=2s.

5.The displacement s of a particle at a time t is given by s=2t-5t+4t-3, find (i) the time when the acceleration is 14 ft/sec (ii) the velocity and the displacement at that time.

From the origin, a particle starts at t = 0 s with a velocity vecv=7.0hatim//s and moves in the xy plane with a constant acceleration of veca=(-9.0hati+3.0hatj)m//s^(2) . At the time the particle reaches the maximum x coordinate, what is its (a) velocity and (b) position vector?

A particle starts from rest and moves with an acceleration of a={2+|t-2|}m//s^(2) The velocity of the particle at t=4 sec is

A particle starts from the origin at t= 0 s with a velocity of 10.0 hatj m//s and moves in the xy -plane with a constant acceleration of (8hati+2hatj)m//s^(-2) . Then y -coordinate of the particle in 2 sec is

A body starts with a velocity (2hati+3hatj+11hatk)m//s and moves with an acceleration (5hati+5hatj-5hatk)m//s^(2) . What is its velocity after 0.2 sec ?

The acceleration of a moving body at any time 't' is given by veca=(4t)hati+(3t^(2))hatj" ""m"//"sec"^(2).If vecU=0 then find the velocity of the prticle at 4 sec.

A particle is moving with initial velocity 1m/s and acceleration a=(4t+3)m/s^(2) . Find velocity of particle at t=2sec .