The acceleration of a moving body at any time 't' is given by `veca=(4t)hati+(3t^(2))hatj" ""m"//"sec"^(2).If vecU=0` then find the velocity of the prticle at 4 sec.

Velocity and acceleration of a particle at time t=0 are u=(2 hati+3 hatj) m//s and a=(4 hati+3 hatj) m//s^2 respectively. Find the velocity and displacement if particle at t=2s.

The position vector of a particle is given by vecr=(3t^(2)hati+4t^(2)hatj+7hatk)m at a given time t .The net displacement of the particle after 10 s is

The velocity of an object is given by vecv = ( 6 t^(3) hati + t^(2) hatj) m//s) . Find the acceleration at t = 2s.

If a man has a velocity varying with time given as v=3t^(2),v is in m//s and t in sec then : Find out the velocity of the man after 3 sec .

The position vector of a particle is given by vec r = (2t hati+5t^(2)hatj)m (t is time in sec). Then the angle between initial velocity and initial acceleration is

The acceleration of paticle varies with time as : a(t) = 3t^(2) +4 If the initial velocity of particle is 2 m//s , find the velocity of particle at t = 3sec .

A particle moves along x-axis and its displacement at any time is given by x(t) = 2t^(3) -3t^(2) + 4t in SI units. The velocity of the particle when its acceleration is zero is

Acceleration of a paritcle moving in x-y plane varies with time t as. vec(a) = (ti + 3T^(2)j) . Here a is in m//s^(2) and t in sec. At time t = 0 particle is at rest origin. Mass of the particles is 1 kg . Find the net work done on the particle in first 2 sec .

The velocity of a particle at t=0 "is"vecU = 4hati+3hatj"m"//"sec" and a constant acceleration is veca=6hati+4hatj"m"//"sec"^(2) . Find the velocity and displacement of the particle at t=2 sec.