A boy throws a ball with velocity `v_(0) =10sqrt2 m//s` at an angle of `45^(@)` as shown in the figure .After collision with the ball the vertical component of ball's velocity is unchanged and the horizontal. Component is reversed in direction .Where does the ball hit the ground?

A ball is projected from the floor of a long hall having a roof height of H = 10 m . The ball is projected with a velocity of u = 25 ms^(–1) making an angle of theta = 37^(@) to the horizontal. On hitting the roof the ball loses its entire vertical component of velocity but there is no change in the horizontal component of its velocity. The ball was projected from point A and its hits the floor at B. Find distance AB.

A volleyball is spiked so that it has an initial velocity of 15 m/s directed downward at an angle of 55^(@) below the horizontal. What is the horizontal component of the ball's velocity when the opposing player fields the ball?

A boy throws a ball at an angle theta with the vertical. If the vertical component of the initial velocity is 20ms^(-1) and the wind imparts a horizontal acceleration of 8ms^(-2) to the left, the angle at which the ball must be thrown so that the ball returns to the boy's hand is theta . What is the value of 10(tan theta)

A ball of mass m moving with velocity v_(0) collides with a wall as shown in Fig. After impact it rebounds with a velocity' (v_(0))//2 The component of impulse acting on the ball along the wall is

Velocity of the ball A after collision with the ball B as shown in the figure is (Assume perfectly inelastic and head - on collision)

Rod can rotate about hinge point 'P'. A ball of mass 'm' is projected with a velocity 5v_(0) in a gravity free space as shown in figure. Collision between the rod and the ball is perfectly elastic. Then find the magnitude of velocity of ball after the collision ( neglect the friction between the ball and the rod during the collision ).

A ball is moving with velocity 2m//s towards a heavy wall moving towards the ball with speed 1m//s as shown in figure. Assuming collision to be elastic, find the velocity of ball immediately after the collision.

A boy throws a ball upward with velocity v_(0)=20m//s . The wind imparts a horizontal acceleration of 4m//s^(2) to the left. The angle theta at which the ball must be thrown so that the ball returns to the boy's hand is : (g=10ms^(-2))