A boy throws a ball upward with velocity...

A boy throws a ball upward with velocity `v_(0)=20m//s`. The wind imparts a horizontal acceleration of `4m//s^(2)` to the left. The angle `theta` at which the ball must be thrown so that the ball returns to the boy's hand is : `(g=10ms^(-2))`

`"tan"^(-1)(1.2)`

`"tan"^(-1)(0.2)`

`"tan"^(-1)(2)`

`"tan"^(-1)(0.4)`

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