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A particle moves in xy-plane. The positi...

A particle moves in xy-plane. The position vector of particle at any time is `vecr={(2t)hati+(2t^(2))hatj}m.` The rate of change of `theta` at time `t = 2` second. ( where 0 is the angle which its velocity vector makes with positive x-axis) is :

A

`2/(17) "rad"//s`

B

`1/(14)"rad"//s`

C

`4/7 "rad"//s`

D

`6/5"rad"//s`

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The correct Answer is:
A
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