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The equation of the circle passing throu...

The equation of the circle passing through the foci ellispe ` x^(2)/16 + y^(2)/9 = 1` having centre at ( 0,3) is

A

`x^(2) + y^(2) - 6y -7 =0`

B

`x^(2) + y^(2) - 6y + 7 = 0`

C

`x^(2) + y^(2) -6y -5 =0`

D

`x^(2) + y^(2) -6y + 5 = 0`

Text Solution

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The correct Answer is:
A
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The equation of the circle passing through the foci of the ellipse ( x ^(2))/( 16) + (y ^(2))/( 9) = 1 having centre at (0,3) is

The radius of the circle passing through the foci of the ellipse (x^2)/(16)+(y^2)/9 and having its center (0, 3) is (a)4 (b) 3 (c) sqrt(12) (d) 7/2

Knowledge Check

  • The radius of the circle passing throgh the foci of the ellipse (x^2)/16 + (y^2)/9 = 1 and haivng centre (0,3) is

    A
    4
    B
    3
    C
    `sqrt(12)`
    D
    `7/2`

  • In an ellispe x^(2)/9 + y^(2)/5 = 1

    A
    Foci ` ( -+ 2,0)`
    B
    a = 9
    C
    Vertrices ` ( -+ 3,0)`
    D
    AA' = 6

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