Find the equation of the plane through the intersection of the planes 2x - 3y + z - = 0 and x - y + z + 1 = 0 and perpendicular to the plane x + 2y - 3z + 6 = 0.

Find the equation of the plane through the line of intersection of the planes x+y+z=1 and 2x+3y+4z=5 which is perpendicular to the plane x-y+z=0

Find the equation of the plane through the intersection of the planes x + 3y + 6 = 0 and 3x - y - 4z = 0 whose perpendicular distance from the orgin is equal to 1.

Find the equation of the plane passing through the intersection of the planes vecr*(2hati+3hatj)=1 and 3x-4y+3z=8 and is perpendicular to the plane x+2y-z+6=0 .

The two planes 3x + 3y - 3z - 1 = 0 and x + y - z + 5 = 0 are

Let P=0 be the equation of a plane passing through the line of intersection of the planes 2x-y=0a n d3z-y=0 and perpendicular to the plane 4x+5y-3z=8. Then the points which lie on the plane P=0 is/are a. (0,9,17) b. (1//7,21//9) c. (1,3,-4) d. (1//2,1,1//3)

The equation of the plane through the line of intersection of the planes ax + by+cz + d= 0 and a'x + b'y+c'z + d'= 0 parallel to the line y=0 and z=0 is

The equation of the plane through the line of intersection of the planes ax + by+cz + d= 0 and a'x + b'y+c'z + d'= 0 parallel to the line y=0 and z=0 is

Find the equation of the plane containing the line of intersection of the planes x + y + z - 6 = 0 and 2x + 3y + 4z + 5 = 0 and passing through the point (1,1,1)

The equation of the plane passing through the intersection of x + 2y + 3x + 4 = 0 and 4x + 3y + 2z+ 1 = 0 and the origin (0.0, 0) is