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Water at temperature 100^(@)C cools in 1...

Water at temperature `100^(@)C` cools in 10 minutes to `80^(@)C` in a room temperature of `25^(@)C`.
Find
(i) The temperature of water after 20 minutes
`[log_(e).(11)/(15)=-0.3101, log_(e)5=1.609]`

Text Solution

Verified by Experts

The correct Answer is:
temperature of water after 20 minutes is `65.33^(@)C`
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