Home
Class 12
MATHS
Suppose the amount of milk sold daily at...

Suppose the amount of milk sold daily at a milk booth is distributed with a minimum of 200 litres and a maximum of 600 litres with probability density function
`f(x)={{:(k, 200 le x le 600), (0, "otherwise"):}`
Find
the probability that daily sales will fall between 300 litres and 500 litres?

Text Solution

Verified by Experts

The correct Answer is:
`1/2`
Promotional Banner

Topper's Solved these Questions

  • PROBABILITY DISTRIBUTIONS

    SURA PUBLICATION|Exercise EXERCISE 11.4|11 Videos
  • PROBABILITY DISTRIBUTIONS

    SURA PUBLICATION|Exercise EXERCISE 11.5|13 Videos
  • PROBABILITY DISTRIBUTIONS

    SURA PUBLICATION|Exercise EXERCISE 11.2|9 Videos
  • ORDINARY DIFFERENTIAL EQUATIONS

    SURA PUBLICATION|Exercise ADDITIONAL QUESTIONS|24 Videos
  • THEORY OF EQUATIONS

    SURA PUBLICATION|Exercise 4 MARKS|5 Videos

Similar Questions

Explore conceptually related problems

Suppose the amount of milk sold daily at a milk booth is distributed with a minimum of 200 litres and a maximum of 600 litres with probability density function f(x)={{:(k, 200 le x le 600), (0, "otherwise"):} Find the value of k

Suppose the amount of milk sold daily at a milk booth is distributed with a minimum of 200 litres and a maximum of 600 litres with probability density function f(x)={{:(k, 200 le x le 600), (0, "otherwise"):} Find the distribution function

Suppose the amount of milk sold daily at a ,mile booth is distributed with a minimum of 200 litres and a maximum of 600 litres with probability density function f(x)= {(k,200lt=xlt=600),(0, "otherwise"):} . Find (i) the value of k (ii) the distribution function (iii) the probability that daily sales will fall between 300 litres and 500 litres ?

The probability density function of X is f(x)={{:(x, 0 lt x lt 1), (2-x, 1 le x lt 2), (0, "otherwise"):} Find P(0.2 le X lt 0.6)

The probability density function of X is f(x)={{:(x, 0 lt x lt 1), (2-x, 1 le x lt 2), (0, "otherwise"):} Find P(0.5 le X lt 1.5)

The probability density function of X is f(x)={{:(x, 0 lt x lt 1), (2-x, 1 le x lt 2), (0, "otherwise"):} Find P(1.2 le X lt 1.8)

If f(x)={{:(2x, 0 le x le a), (0, "otherwise"):} is a probability density function of a random variable, then the value of a is