x=y^(n-1)=24," then "(2x)^(2)

If 2x=y^(1//n)," then: "x^(2)(y_(1))^(2)=

If y=cos^(-1)((x^(2n)-1)/(x^(2n)+1)))," then "(1+x^(2n))y_(1)=

If y^((1)/(n))+y^(-(1)/(n))=2x then (x^(2)-1)y_(2)+xy_(1) is equal to

If y^(1/n)+y^(-1/n) = 2x then (x^2-1)y_2+xy_1 is equal to

If y=x^(n-1)ln x then x^(2)y_(2)+(3-2n)xy_(1) is equal to -(n-1)^(2)y(b)(n-1)^(2)y-n^(2)y(d)n^(2)y

If y=x^(n-1)lnx then x^2y_2+(3-2n)x y_1 is equal to (a) -(n-1)^2y (b) (n-1)^2y (c) -n^2y (d) n^2y

If |[x^(n-1), x^(n+1), x^(n+2)] ,[y^(n-1), y^(n+1), y^(n+2)], [z^(n-1), z^(n+1), z^(n+2)]|= (x-y)(y-z)(z-x)(x^(-1)+y^(-1)+z^(-1)) then n=

If x + y = 1, show that D ^ (n) (x ^ (n) y ^ (n)) = n! [Y ^ (n) - (nC_ (1)) ^ (2) y ^ (n -1) x + (nC_ (2)) ^ (2) y ^ (n-2) x ^ (2) + ...... + (- 1) ^ (n) x ^ (n)]

If (1 +px)^(n) = 1 + 24x + 264x^(2) + .. . then

If x and y are positive with x-y=2 and xy=24, then frac(1)(x) + frac(1)(y) is equal to