" Find the value of "k" if "f(x)" is continuous at "x=pi/2," where "f(x)={[(k cos x)/(pi-2x),x!=pi/2],[3,,x=pi/2]

Find the value of k if f(x) is continuous at x=pi/2, where f(x)={(k cos x)/(pi-2x),quad x!=pi/23,quad x=pi/2

Find the value of k if f(x) is continuous at x=pi//2 , where f(x)={(kcosx)/(pi-2x),x!=pi/2 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3, \ \ \ \ \ \ \ \ \ x=pi/2

If f(x) is continuous at x=pi/2 , where f(x)=(cos x )/(sqrt(1-sinx)) , for x!= pi/2 , then f(pi/2)=

If f(x) is continuous at x=pi/2 , where f(x)=(1-sin x)/((pi-2x)^(2)) , for x != pi/2 , then f(pi/2)=

Find the value of k if f(x) is a continious function give by f(x)={((kcosx)/(pi-2x),xnepi/2),(3,x=pi/2):} at x=pi/2

If f(x) is continuous at x=pi/2 , where f(x)=(1-sin x)/((pi/2 -x)^(2)) , for x!= pi/2 , then f(pi/2)=

If f(x) is continuous at x=pi/4 , where f(x)=(1+cos 2x)^(4sec 2x) , for x!= pi/4 , then f(pi/4)=

Find the value of k so that the function f is continuous at x=pi//2,f(x)={:{((kcosx)/(pi-2x)", if "x!=(pi)/(2)),(5", if "x=(pi)/(2)):}