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(3x)/2-(5y)/3=-2, x/3+y/2=13/6...

`(3x)/2-(5y)/3=-2`, `x/3+y/2=13/6`

Text Solution

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`(3x)/2 - (5y)/3 = -2 ->(1)`
`x/3+y/2 = 13/6->(2)`
Multiplying (1) with `12` and (2) with `54` and then subtracing (2) from (1),
`18x-20y-18x-27y = -24-117`
`=>-47y = -141 => y = 3`
Putting value of `y` in (1),
`(3x)/2 - 5 = -2 => 3x = 6 => x = 2`
`:. x = 2, y = 3`.
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