Prove that : `sintheta/(cos(3theta)) + (sin3theta ) /(cos9theta) + (sin 9theta) /(cos27theta) =1/2( tan27theta-tantheta)`

Prove that sintheta/(cos3theta)+(sin3theta)/(cos9theta)+(sin9theta)/(cos27theta)=1/2(tan27theta-tantheta)

Prove that :(sin theta)/(cos(3 theta))+(sin3 theta)/(cos9 theta)+(sin9 theta)/(cos27 theta)=(1)/(2)(tan27 theta-tan theta)

Prove that : sin theta/cos(3theta) +sin (3theta)/cos (9theta) + sin(9theta)/cos( 27theta )= 1/2(tan27 theta -tan theta)

Show that, (sin theta)/(cos 3 theta) + (sin 3 theta)/(cos 9 theta) + (sin 9 theta)/(cos 27 theta) = 1/2 ( tan 27 theta - tan theta).

Prove that : sintheta/cos(3theta)+sin(3theta)/cos(9theta)+sin(9theta)/cos(27theta)=1/2(tan(27theta)-tan(theta))

Prove that : (sin theta)/(cos[3 theta])+(sin[3 theta])/(cos[9 theta])+(sin[9 theta])/(cos[27 theta])=(1)/(2)[tan[27 theta]-tan[theta]]

(sin theta)/(cos3theta)+(sin3theta)/(cos9theta)+(sin9theta)/(cos27theta)+(sin27theta)/(cos81theta)=

(sin theta)/(cos3 theta)+(sin3 theta)/(cos9 theta)+(sin9 theta)/(cos27 theta)+(sin27 theta)/(cos81 theta)=

(sin theta)/(cos(3theta))+(sin(3theta))/(cos(9theta))+(sin(9theta))/(cos(27theta))+(sin(27theta))/(cos(81theta))=

(sin theta)/(cos(3theta))+(sin(3theta))/(cos(9theta))+(sin(9theta))/(cos(27theta))+(sin(27theta))/(cos(81theta))=