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[" 5.In "18^(@)],[cos72^(@)]...

[" 5.In "18^(@)],[cos72^(@)]

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Evaluate : (sin 18^(@))/(cos72^(@))

cos36^(@)-cos72^(@)=

Evaluate : (sin 18^(@))/(cos 72^(@))

Evaluate: (i) (sin 18^(@))/(cos 72^(@))

Evaluate : (sin 18^@)/(cos 72^@)

Find the Value of sin18^(@) or cos72^(@)

Evaluate: (sin18^(@))/(cos72^(@))

Evalute: (b) (sin18^(@))/(cos72^(@))

Prove that (sin18^(@))/(cos72^(@))=1