[(ax+by)=3a+2b],[6(bx-by)-3b-29]

6(ax+by)=3a+2b&6(bx-ay)=3b-2a

Solve the following equations by Elimination method : 6(ax+by)=3a+2b 6(bx-ay)=3b-2a .

Solve the following system of equations by method of cross-multiplication: 6(ax+by)=3a+2b,quad 6(bx-ay)=3b-2a

ax+by=a+b bx+ay=b^2

Solve: (x^2-ax)/b+(x^2-bx)/a+(x^2-3ax-3bx)/(a+b)=0 ]

|{:(a,b,ax+by),(b,c,bx+cy),(ax+by,bx+cy,0):}|=(b^2-ac)(ax^2+2bxy+cy^2)

Prove that |(a,b,ax+by),(b,c,bx+cy),(ax+by, bx + cy, 0)| = (b^(2)-ac)(ax^(2) + 2bxy + cy^(2)) .

Factorise : ax + 2bx + 3cx - 3a - 6b - 9c

if x = (sqrt(3a + 2b) + sqrt(3a - 2b))/(sqrt(3a + 2b) - sqrt(3a - 2b)) prove that : bx^(2) - 3ax + b = 0